Ln(x^2+2)-lnx^2=2

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Solution for Ln(x^2+2)-lnx^2=2 equation: 


Simplifying
Ln(x2 + 2) + -1lnx2 = 2

Reorder the terms:
nL(2 + x2) + -1lnx2 = 2
(2 * nL + x2 * nL) + -1lnx2 = 2
(2nL + nx2L) + -1lnx2 = 2

Reorder the terms:
-1lnx2 + 2nL + nx2L = 2

Solving
-1lnx2 + 2nL + nx2L = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2nL' to each side of the equation.
-1lnx2 + 2nL + -2nL + nx2L = 2 + -2nL

Combine like terms: 2nL + -2nL = 0
-1lnx2 + 0 + nx2L = 2 + -2nL
-1lnx2 + nx2L = 2 + -2nL

Add '-1nx2L' to each side of the equation.
-1lnx2 + nx2L + -1nx2L = 2 + -2nL + -1nx2L

Combine like terms: nx2L + -1nx2L = 0
-1lnx2 + 0 = 2 + -2nL + -1nx2L
-1lnx2 = 2 + -2nL + -1nx2L

Divide each side by '-1nx2'.
l = -2n-1x-2 + 2x-2L + L

Simplifying
l = -2n-1x-2 + 2x-2L + L

Reorder the terms:
l = L + -2n-1x-2 + 2x-2L

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